Open Project in VSCode Script

As requested by John: https://twitter.com/johnlindquist/status/1381251960817418246

I have my projects in ~/code and temporary projects in ~/Desktop. Sometimes they're in sub-directories as well. Every project has a root-level package.json, so I put together this script to quickly open a project in vscode:

// Menu: Open Project
// Description: Opens a project in code
// Shortcut: cmd shift .

async function getProjects(parentDir) {
  const codeDir = await ls(parentDir)
  const choices = []
  for (const dir of codeDir) {
    if (dir.includes('node_modules')) continue

    const fullPath = path.join(parentDir, dir)
    if (await isFile(path.join(fullPath, 'package.json'))) {
      choices.push({
        name: dir,
        value: fullPath,
        description: fullPath,
      })
    } else {
      choices.push(...(await getProjects(fullPath)))
    }
  }
  return choices
}

const choice = await kitPrompt({
  placeholder: 'Which project?',
  choices: [
    ...(await getProjects('~/code')),
    ...(await getProjects('~/Desktop')),
  ],
})

exec(`code ${choice}`)

Works great!